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📐 Mathematics Binomial Theorem Medium JEE Advanced custom
Question #24
If $\binom{30}{1}^{2}+2\binom{30}{2}^{2}+3\binom{30}{3}^{2}+...+30\binom{30}{30}^{2}=\frac{\alpha(60!)}{(30!)^{2}}$ then $\alpha$ is equal to
Choose the correct answer
A
30
B
60
C
15
D
10
Hint
Use Reversal Method for summation.
Step-by-Step Solution

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Question Info
SubjectMathematics
TopicBinomial Theorem
DifficultyMedium
Typesingle_correct
ExamJEE Advanced
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