If $\binom{30}{1}^{2}+2\binom{30}{2}^{2}+3\binom{30}{3}^{2}+ | Mathematics

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Question #24

If $\binom{30}{1}^{2}+2\binom{30}{2}^{2}+3\binom{30}{3}^{2}+...+30\binom{30}{30}^{2}=\frac{\alpha(60!)}{(30!)^{2}}$ then $\alpha$ is equal to

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Question Info

SubjectMathematics

TopicBinomial Theorem

DifficultyMedium

Typesingle_correct

ExamJEE Advanced

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