📚 Question Bank

Let $f:R\to \left( 0,\infty \right)$ be such that $f\left( x \right)+\frac{e^{x+x^{2}}}{f\left( x \right)}\le e^{x}+e^{x^{2}}, \forall$ $x>0$. Then, $\displaystyle\lim_{x \to 1} f\left( x \right)$ is

If $\binom{30}{1}^{2}+2\binom{30}{2}^{2}+3\binom{30}{3}^{2}+...+30\binom{30}{30}^{2}=\frac{\alpha(60!)}{(30!)^{2}}$ then $\alpha$ is equal to