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⚡ DAILY CHALLENGE - 04 FEB 2026

If $\binom{30}{1}^{2}+2\binom{30}{2}^{2}+3\binom{30}{3}^{2}+...+30\binom{30}{30}^{2}=\frac{\alpha(60!)}{(30!)^{2}}$ then $\alpha$ is equal to

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